x^2-16x+10=4

Solution for x^2-16x+10=4 equation:

x^2-16x+10=4

We move all terms to the left:

x^2-16x+10-(4)=0

We add all the numbers together, and all the variables

x^2-16x+6=0

a = 1; b = -16; c = +6;
Δ = b2-4ac
Δ = -162-4·1·6
Δ = 232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{232}=\sqrt{4*58}=\sqrt{4}*\sqrt{58}=2\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{58}}{2*1}=\frac{16-2\sqrt{58}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{58}}{2*1}=\frac{16+2\sqrt{58}}{2}
$